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Algebra 1 answers to Chapter 2 - Solving Equations - 2-3 Solving Multi-Step Equations - Practice and Problem-Solving Exercises - Page 98 32 including work step by step written by community members like you. Textbook Authors: Hall, Prentice, ISBN-10: 0133500403, ISBN-13: 978-0-13350-040-0, Publisher: Prentice Hall

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The more challenging Algebra 1 problems are quadratic equations of the form ax^2 +bx +c =0, where the general solution is given by the quadratic formula: x = (-b +/- sqrt(b^2-4ac))...Table 1.4.1. Terms88 in an algebraic expression are separated by addition operators and factors89 are separated by multiplication operators. The numerical factor of a term is called the coefficient90. For example, the algebraic expression x2y2 + 6xy − 3 can be thought of as x2y2 + 6xy + ( − 3) and has three terms.

Algebra 1 answers to Chapter 6 - Systems of Equations and Inequalities - 6-3 Solving Systems Using Elimination - Lesson Check - Page 377 1 including work step by step written by community members like you. Textbook Authors: Hall, Prentice, ISBN-10: 0133500403, ISBN-13: 978-0-13350-040-0, Publisher: Prentice Hall

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David Severin. 2 years ago. The rule for dividing same bases is x^a/x^b=x^ (a-b), so with dividing same bases you subtract the exponents. In the case of the 12s, you subtract -7- (-5), so two negatives in a row create a positive answer which is where the +5 comes from. In the x case, the exponent is positive, so applying the rule gives x^ (-20-5).

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